Top Chord Force by the Method of Sections
A simply supported truss spans in four equal panels, with a constant height of .
Bottom-chord joints are at , , , , . Top-chord joints are at , , .
A downward load of acts at each of , , and . Supports are at (pin) and (roller).
Find the force in top chord member , and state tension or compression.
| P | 20 kN | Load at each interior bottom joint |
| h | 4 m | Truss height |
| L | 12 m | Span |
Hint 1
The method of sections lets you reach an interior member directly, without working joint by joint.
Hint 2
Cut through the panel containing U₁U₂, then pick a moment centre that eliminates the other two cut members.
Hint 3
Moments about L₂ kill both the diagonal and the bottom chord, leaving only the top chord.
Worked solution — try the problem first
Reactions. Total load kN, symmetric, so
Cut vertically between and , severing , the diagonal, and . Keep the left segment.
Take moments about . This is the key choice: the diagonal and the bottom chord both pass through , so they contribute no moment and is the only unknown left.
Forces on the left segment, with counterclockwise positive:
- kN up at , lever arm 6 m:
- Load 20 kN down at , lever arm 3 m:
- acting horizontally at height 4 m: (taking tension positive)
The negative sign means the assumed tension is wrong:
Sanity check. The top chord of a simply supported truss under gravity load is always in compression, and the bottom chord in tension — the truss behaves like a beam, with the top in compression above the neutral axis.
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