EEngiGrind
← All problems
CivilStructural AnalysishardFE ExamCourseworkPE / Advanced

Top Chord Force by the Method of Sections

A simply supported truss spans 12 m12\ \text{m} in four equal 3 m3\ \text{m} panels, with a constant height of 4 m4\ \text{m}.

Bottom-chord joints are at L0(0,0)L_0(0,0), L1(3,0)L_1(3,0), L2(6,0)L_2(6,0), L3(9,0)L_3(9,0), L4(12,0)L_4(12,0). Top-chord joints are at U1(3,4)U_1(3,4), U2(6,4)U_2(6,4), U3(9,4)U_3(9,4).

A downward load of 20 kN20\ \text{kN} acts at each of L1L_1, L2L_2, and L3L_3. Supports are at L0L_0 (pin) and L4L_4 (roller).

Find the force in top chord member U1U2U_1U_2, and state tension or compression.

Given
P20 kNLoad at each interior bottom joint
h4 mTruss height
L12 mSpan
Hint 1

The method of sections lets you reach an interior member directly, without working joint by joint.

Hint 2

Cut through the panel containing U₁U₂, then pick a moment centre that eliminates the other two cut members.

Hint 3

Moments about L₂ kill both the diagonal and the bottom chord, leaving only the top chord.

Worked solution — try the problem first

Reactions. Total load =3×20=60= 3 \times 20 = 60 kN, symmetric, so

RL0=RL4=30 kNR_{L_0} = R_{L_4} = 30\ \text{kN}

Cut vertically between x=3x = 3 and x=6x = 6, severing U1U2U_1U_2, the diagonal, and L1L2L_1L_2. Keep the left segment.

Take moments about L2(6,0)L_2(6,0). This is the key choice: the diagonal and the bottom chord both pass through L2L_2, so they contribute no moment and U1U2U_1U_2 is the only unknown left.

Forces on the left segment, with counterclockwise positive:

  • RL0=30R_{L_0} = 30 kN up at x=0x = 0, lever arm 6 m: 30(6)=180-30(6) = -180
  • Load 20 kN down at L1L_1, lever arm 3 m: +20(3)=+60+20(3) = +60
  • FU1U2F_{U_1U_2} acting horizontally at height 4 m: 4F-4F (taking tension positive)

ML2=0:4F180+60=0\sum M_{L_2} = 0: \quad -4F - 180 + 60 = 0 4F=120F=30 kN-4F = 120 \quad \Longrightarrow \quad F = -30\ \text{kN}

The negative sign means the assumed tension is wrong:

FU1U2=30 kN compression\boxed{F_{U_1U_2} = 30\ \text{kN compression}}

Sanity check. The top chord of a simply supported truss under gravity load is always in compression, and the bottom chord in tension — the truss behaves like a beam, with the top in compression above the neutral axis.

Concepts:Method of sectionsTruss analysisStatic equilibrium

Sign in to submit

Grading needs an account so your progress, attempts, and daily quota can be tracked. The problem statement and worked solution stay open to everyone.

Create an account