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CivilStructural AnalysiseasyFE ExamCoursework

Bending Moment Under a Point Load

A simply supported beam spans L=10 mL = 10\ \text{m}. A single point load of P=40 kNP = 40\ \text{kN} acts 3 m3\ \text{m} from the left support.

Find the bending moment at the location of the load.

Given
P40 kNPoint load
L10 mSpan
a3 mDistance from left support to load
Hint 1

Find the support reactions first, then cut the beam at the load.

Hint 2

R_A = Pb/L, where b is the distance from the load to the far support.

Hint 3

The standard result is M = Pab/L.

Worked solution — try the problem first

Reactions. Taking moments about the right support:

RA=PbL=40×710=28 kNR_A = P\frac{b}{L} = 40 \times \frac{7}{10} = 28\ \text{kN}

The reaction nearer the load is the larger one — note RAR_A uses b=7b = 7 m, the distance to the far support.

Moment at the load. Cut just left of the load and take moments:

M=RA×a=28×3=84 kN⋅mM = R_A \times a = 28 \times 3 = 84\ \text{kN·m}

M=84 kN⋅m\boxed{M = 84\ \text{kN·m}}

Check with the standard formula:

M=PabL=40×3×710=84 kN⋅m M = \frac{Pab}{L} = \frac{40 \times 3 \times 7}{10} = 84\ \text{kN·m} \ \checkmark

For a single point load the moment peaks at the load, so this is also the maximum moment in the beam.

Concepts:Bending moment diagramsSupport reactionsPoint loads

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